Question

10. In an A.P. 17th term is 7 more than its 10h term. Find the common difference.​

Answer 1

Step-by-step explanation:

We know that, for an A.P series

We know that, for an A.P seriesan = a+(n−1)d

We know that, for an A.P seriesan = a+(n−1)da17 = a+(17−1)d

We know that, for an A.P seriesan = a+(n−1)da17 = a+(17−1)da17 = a +16d

We know that, for an A.P seriesan = a+(n−1)da17 = a+(17−1)da17 = a +16dIn the same way,

We know that, for an A.P seriesan = a+(n−1)da17 = a+(17−1)da17 = a +16dIn the same way,a10 = a+9d

We know that, for an A.P seriesan = a+(n−1)da17 = a+(17−1)da17 = a +16dIn the same way,a10 = a+9dAs it is given in the question,

We know that, for an A.P seriesan = a+(n−1)da17 = a+(17−1)da17 = a +16dIn the same way,a10 = a+9dAs it is given in the question,a17 − a10 = 7

We know that, for an A.P seriesan = a+(n−1)da17 = a+(17−1)da17 = a +16dIn the same way,a10 = a+9dAs it is given in the question,a17 − a10 = 7Therefore,

We know that, for an A.P seriesan = a+(n−1)da17 = a+(17−1)da17 = a +16dIn the same way,a10 = a+9dAs it is given in the question,a17 − a10 = 7Therefore,(a +16d)−(a+9d) = 7

We know that, for an A.P seriesan = a+(n−1)da17 = a+(17−1)da17 = a +16dIn the same way,a10 = a+9dAs it is given in the question,a17 − a10 = 7Therefore,(a +16d)−(a+9d) = 77d = 7

We know that, for an A.P seriesan = a+(n−1)da17 = a+(17−1)da17 = a +16dIn the same way,a10 = a+9dAs it is given in the question,a17 − a10 = 7Therefore,(a +16d)−(a+9d) = 77d = 7d = 1

Answer 2

Answer:

let a is the 1st term and d i is the common difference

so,17 th term =a+(17-1)d=a+16d

and 10 th term =a+(10-1)d=a+9d

according to question,(a+16d)-(a+9d)=7

=.> a+16d-a-9d=7

=> 7d=7

=> d=7/7=1

so the common difference is 1