Question

10. In an A.P. the 20th term
is 14 more than its
13th term. Find the common difference.
Ans​

Answer 1

Step-by-step explanation:

tn=a+(n-1)d

t20=a+19d

t13=a+12d

t20=t13+14

a+19d=a+12d+14

19d-12d=14

7d=14

d=2

hence common difference is 2

Answer 2

Given:-

• The 20th term of an A.P is 14 more than its 13th term.

To Find:-

• It's Common Difference

Formula used:-

• $a_n=a(n-1)d$

Solution:-

According to question,

$⟹a_{20}=14+a_{13}$

$⟹a+(20-1)d=14+a+(13-1)d$

$⟹a+(20-1)d=14+a+(13-1)d$

$⟹20d-d=14+13d-d$

$⟹20d=14+13d$

$⟹20d-13d=14$

$⟹7d=14$

$⟹d=\dfrac{14}{7}$

${\boxed{⟹d=2}}$

Hence, The Common Difference according to the given data is 2.

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