Question

10. In the figure, AD is the median of traingle ABC. BE and
CF are perpendiculars from B and C on AD and AD produced. Prove that BE = CF.​







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Answer 1

Step-by-step explanation:

To prove: BE = CF

Proof : In ΔDEB and ΔABC

AD is the median of ΔABC

Angle DEB = Angle DFC | Each = 90°

AngleBDE = AngleCDF

| veritically opposite angles

hence , ΔDEB is congruent to ΔDFC

| AAS congruence rule is applied

thus , BE = CF | C.P.C.T

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