Physics, asked by mohdsaifa068, 6 hours ago

10 joul work is done on moving the charge of 2 microcoulomb from point a to point b if the potential at point a is 5 volt what is the potential at b?​

Answers

Answered by NewGeneEinstein
1

Answer:-

  • Work=W=10J
  • Charge=C=2\mu
  • \sf V_a=5V
  • \sf V_b=?

We know that

\boxed{\sf V=V_a+V_b}

\boxed{\sf V=\dfrac{W}{Q}}

\\ \tt\longmapsto V_a+V_b=\dfrac{10}{2}

\\ \tt\longmapsto 5+V_b=5

\\ \tt\longmapsto V_b=5-5

\\ \tt\longmapsto V_b=0V

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