Question

10 labourers can complete a work in 21 days. The completion of the work is planned such that only 1 labour is engaged on the 1 days, 2 labourers on the 2 nd day, 3 labourers on the 3 rd day and so on. Find the number of days required to complete the work according to the given plan

Answer 1

Answer:

149.5 days

Step-by-step explanation:

Brilliant question.

Explanation :

1 labourer's 1 day work = 10/21

MDH/W = mdh/w

10*21/1 =[ 1^1/ +2^2 + ... n^n ]

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1*(10/21) + 2*(10/21)+ ..

or, 210 = n(n+1)(2n+1)/6

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(10/21)(1+2+.....+n)

210 = (2n+1)*21*2

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60

n= 299/2 = 149.5 days

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