Question

A heating element is marked 210v 630w what is the value of the current drawn by the element when connected to a 210 v dc siurce

Answer 1

Answer:

The power of the heating element is 630 Watt and its voltage is 210 V. Thus, the current drawn can be calculated with the formula

The power of the heating element is 630 Watt and its voltage is 210 V. Thus, the current drawn can be calculated with the formula P = VI,

The power of the heating element is 630 Watt and its voltage is 210 V. Thus, the current drawn can be calculated with the formula P = VI, where P denotes the power, V stands for the voltage and I is the symbol of the current.

The power of the heating element is 630 Watt and its voltage is 210 V. Thus, the current drawn can be calculated with the formula P = VI, where P denotes the power, V stands for the voltage and I is the symbol of the current. So the value of the current drawn = P / V = 630 / 210 = 3 Ampere.

The power of the heating element is 630 Watt and its voltage is 210 V. Thus, the current drawn can be calculated with the formula P = VI, where P denotes the power, V stands for the voltage and I is the symbol of the current. So the value of the current drawn = P / V = 630 / 210 = 3 Ampere.Read more on Brainly.in - https://brainly.in/question/178489#readmore

Answer 2

Answer:-

I = 3.14 A

Given :-

V = 210 v

P = 630 w

To find :-

The current drawn by the element.

Solution:-

First, we have to find the resistance of the heating element.

By using the power - Resistance formula.

→$P = \dfrac{v^2}{R}$

• Put the given value.

→$630 = \dfrac{(210)^2}{R}$

→$630 = \dfrac{44,100}{R}$

→$R = \dfrac{44,100}{630}$

→$R = 70 \Omega$

hence,

The resistance of heating element is 70 $\Omega$.

• By using Ohm's law.

The current drawn by heating element is:-

→$v = IR$

→$210 = I \times 70$

→$I = \dfrac{220}{70}$

→$I = 3.14 A$

hence,

The current drawn by heating element is 3.14 A.