Question

10. Let n(A) = 31, n(B) = 20 and n(AnB) = 6, find :
(0) n(A - B)
(ii) n(B - A) (iii) n(AUB)​

Answer 1

Answer:

Step-by-step explanation:

1) n(A-B)=n(A)-n(AnB)=31-6=25

2). n(B-A)=n(B)-n(AnB)=20-6=14

3). n(AUB)=n(A)+n(B)-n(AnB)=31+20-6=45