10 lit of water per second is lifted from a well through 10 m and delivered with the velocity of 10 m/s. then what will the power of the mother.
Answers
Answer:
1500 W OR 1.5 kW is the correct answer.
Explanation:
⇒ In this case,
Power = [Work Done] ÷ [Time]
⇒ Power = [(m × g × h) + (1/2 × m × v²)] ÷ [Time]
⇒ Power = m × [(g × h) + (1/2 × v²)] ÷ [Time]
Mass of Water = Density of Water × Volume of Water
= 1000 kg/m³ × 10 dm³ [∵ 1 litre = 1 dm³]
= 1000 kg/m³ × 0.01 m³ [∵ 1 dm³ = 0.001 m³]
= 10 kg
⇒ Power = m × [(g × h) + (1/2 × v²)] ÷ [Time]
⇒ Power = 10 kg × [(10 m/s² × 10 m) + (1/2 × 100 m²/s²)] ÷ 1 s
⇒ Power = 10 kg × [100 m²/s² + 50 m²/s²] ÷ 1 s
⇒ Power = [10 kg × 150 m²/s²] ÷ 1 s
⇒ Power = 1500 kg m²/s² ÷ 1 s
⇒ Power = 1500 kg m²/s³
= 1500 J/s
= 1500 W OR 1.5 kW ←ANSWER