10 men and 15 women finish a work in 6 days. One man alone finishes that work in 100 days that same work. In how many days will a women finish the work?
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Answer:
1 men can finish the whole work in 100 days
Therefore 1 man's 1 days' work = 1/100
=> 10 men's 1 days' work
= 10 × 1/100 = 1/10
Let the time taken by one women to finish the work be x days.
Then, 1 woman's days' work = 1/x
=> 15 women's 1 days' work = 15/x
Given, ( 10 men's + 15 women's ) 1 days' work = 1/6
=> 1/10 + 15/x = 1/6
=> 1/10 + 15/x = 1/6
=> 15/x = 1/6 – 1/10
= 2/30
= 1/15
=> x = 225 days.
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