10 men can complete a piece of work in 34 days, 16 women can complete the same piece of work in 56 days. 5 men and 18 women work together for 20 days. If only women were to complete the remaining piece of work in 4 days along with a boy who does 10 units of work per day, how many women would be required?
Answers
Given : 10 men can complete a piece of work in 34 days, 16 women can complete the same piece of work in 56 days. 5 men and 18 women work together for 20 days.
To find : Remaining piece of work in 4 days along with a boy who does 10 units of work per day, how many women would be required
Solution:
10 men can complete a piece of work in 34 days
=> Total Work = 10 * 34 = 340 Man Days
16 women can complete the same piece of work in 56 days.
=> Total Work = 16 * 56 = 896 Woman days
340 Man Days = 896 Woman days
=> 85 Man = 224 Woman
=> 1 Man = 224/85 Woman
5 men and 18 women work together for 20 days
= 100 Man days + 360 Woman Days
= 100(224/85) + 360 Woman Days
= 53000/85 Woman days
Work remaining = 896 - 53000/85 Woman days
= 23160/85 Woman days
a boy who does 10 units of work per day 40 units
(not clear what is the exact meaning )
Assuming (23160 - 40)/85 = 272
Remaining Work to be done in 4 days by W woman = 4W woman days
4W = 272
=> W = 68 so 68 Woman required
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