x-1/9x=1 find 27x^3-1/27x^3
Answers
Answered by
4
Hope u like my process
=====================
Formula to be used
=-=-=-=-=-=-=-=-=-=-==
=> a³ - b³ =(a-b)³ +3ab(a-b)
_____________________

Hope this is ur required answer
Proud to help you
=====================
Formula to be used
=-=-=-=-=-=-=-=-=-=-==
=> a³ - b³ =(a-b)³ +3ab(a-b)
_____________________
Hope this is ur required answer
Proud to help you
Similar questions
Math,
9 months ago
Social Sciences,
9 months ago
Chinese,
9 months ago
Math,
1 year ago
Hindi,
1 year ago
CBSE BOARD X,
1 year ago