10 men can complete a work in 48 days.16 women can complete the same piece of work in 60 days .8 men and 20 women work together for 20 days.if only women were to
Answers
Given :
Time taken by 10 men to complete a work = 48 days
Time taken by 16 women to complete the same piece of work = 60 days
Time taken by 8 men and 20 women to complete a work = 20 days
To Find :
No. of women required to complete the remaining work in four days
Solution :
Total work = (No. of person) × Time
Work done by men = 10 Men × 48
Work done by women = 16 Women × 60
As per question,
10 Men × 48 = 16 Women × 60
1 Men = 2 Women
So, 1 man work = 2 women work.
Total work done by 8 men and 20 women in 20 days = (8 + 10) × 20
= 360 units.
Total required work = 10 × 48 = 480 units
Work left = (480 - 360) = 120 units
30 men can complete this remaining work in 4 days
So, Women required = 30 × 2 [since 1 man work = 2 women work]
= 60 women
Therefore, 60 women are required to complete the remaining work in four days.
Note : The question given is incomplete. The full question is -
10 men can complete a work in 48 days. 16 women can complete the same piece of work in 60 days. 8 men and 20 women work together for 20 days, if only the women were to complete the remaining work in 4 days, then how many women would be required?