4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. in how many days will 10 women complete it? 35 40 45 50
Answers
Answered by
0
(4M+6W)8 = (3M+7W)10
32M+48W = 30M+70W
32M-30W = 70W-48W
2M = 22W
M = 11W
4*11W+6W=8
50W=8
10W = 8*5=40
32M+48W = 30M+70W
32M-30W = 70W-48W
2M = 22W
M = 11W
4*11W+6W=8
50W=8
10W = 8*5=40
Answered by
3
Let the work done by 1 men in 1-day be x.
Let the work done by 1 women in 1-day be y.
Given,
4x + 6y = 1/8 ----- (1)
3x + 7y = 1/10 ----- (2)
On solving (1) * 3 & (2) * 4, we get
12x + 28y = 4/10
12x + 18y = 3/8
-----------------------
10y = 1/40
y = 1/400.
Now,
We got 1 women's 1-day work = 1/400.
Then 10-women's 1-day work = 1/400 * 10
= 1/40.
Therefore 10 women can complete the work in 40 days.
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