Question

10 men can finish the construction of a wall in 8 days. How many men are added to finish the work in half a day?​

Answer 1

Answer :- 150.

Given :- 10 men can finish the construction of a wall in 8 days.

To find :- How many men are added to finish the work in half a day?

Solution :-

Let the no of men added to fish the work in half day be 'x' .

Men who can finish in 1 day ,

So ,. 10×8=80.

Men who can finish in half day = 80×2 = 160.

Therefore, Men added to finish work in half day :-

$\implies$ 160-10 = 150.

Hence , Ans is 150.

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HOPE IT HELPS :)

Answer 2

Answer:

$\large\bf\underline\red{Question➡} \\ \\ \bf \: 10 \: men \: can \: finish \: the \: \\ \bf construction \: of \: a \: wall \: in \: 8days. \\ \bf \: how \: many \: men \: are \: added \\ \bf \: to \: finish \: the \: in \: half \: day \: ? \\ \\ \large\bf\underline\red{solution➡} \\ \\ \sf\underline\blue{(number \: of \: men \: is \: inversely } \\ \sf\underline\blue{proportional \: to \:no. \: of \: days) } \\ \\\bf let \\ \bf \: x = no. \: of \: men \: \\ \bf \: y = no. \: of \: days \: \\ \\ \bf \: ∴ \: \: \: y = \frac{k}{x} \\ \\ \sf \: 8 = \frac{k}{10} \\ \\\sf k \: = 80 \\ \\ \sf\red{(so \: when \:finish \: the \:work \: in \: half } \\ \sf\red{day \: the \: men \: required \: are \:➡ } \\ \\ \sf \: y = \frac{k}{x} \\ \\ \sf \frac{1}{2} = \frac{80}{x} \\ \\ \sf{\small{\fbox{\red{x = 160}}}} \\ \\ \bf{the \: no. \: of \: men \: added \: is \:➡ } \\ \\ \sf \: 160 - 10 = 150 \\ \\ \sf \: so \: the \: answer \: is \: ➡ \small{\boxed{\mathfrak\red{\fcolorbox{magenta}{aqua}{150 \: men \: }}}}$