Question

In triangle PQR ,find TanP -Cos R

Answer 1

Answer:

0

Step-by-step explanation:

Let's imagine a right angle triangle PQR  in which Q is 90 degree

$Tan P = \frac{QR}{PQ} \\Cot R = \frac{QR}{PQ} \\A/Q \\\\Tan P -Cot R= \frac{QR}{PQ} - \frac{QR}{PQ}\\= 0$