Question

10 men complete a certain work witthin 4 days how many days will it takes for8 men to complete a work which is twice the magnitude of above mentioned work

Answer 1

Answer:

10 days

Step-by-step explanation:

m = no of men

d = no of days

w = work

m1 = 10 men

d1 = 4 days

w1 = x

w2 is twice the magnitude of w1 (2x)

m2 = 8 men

$\frac{m1 \: d1 \: h1}{w1} = \frac{m2\: d2\: h2}{w2}$

$\frac{10\times 4}{x} = \frac{8 \times y}{2x}$

$y = 10 \: days$

Answer 2

Answer:

5 days

Step-by-step explanation:

let per day one man work be x

since 10 men complete the work in 4 days

therefore total work = 10x × 4 = 40x

therefore time taken by 8 men

= total work ÷ per day work done by 8 men

= 40x ÷ 8x = 5 days