Question

10 ml of 0.1 N HCL is added to 990 ml solution of NaCl the pH of the resulting solution is

Answer 1

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Answer 2

Answer:

6

Explanation:

Ph = -  log p Ka

4 = - log p Ka

[ H+] =  10⁻⁴ mol/ l

C = 10⁻⁴ / (990 + 10) = 10⁻⁶ mol/l

Ph = -  log p Ka

Ph = -  log 10⁻⁶

Ph = 6

Hence the ph of the solution is 6.