Question

10 ml of 0.2 N HClHCl and 30 ml of 0.1 N HClHCl together exactly neutralise 40 ml of a solution of NaOHNaOH, which is also exactly neutralized by a solution in water of 0.61 g of an organic acid. The equivalent weight of the organic acid is :

Answer 1

Answer:

1geqHCl≡1geqNaOH≡geqacid

The number of g eq of HCl =

1000mL/L

10mL

×0.2N+

1000mL/L

30mL

×0.1N=0.005eq

This corresponds to 0.005 g eq of acid.

The equivalent weight of the acid is

0.005geq

0.61g

=122