Question

10 ml of a compound containing N and O is mixed with 30 ml of H2 to produce H20 (l) and 10 ml of N2 (g). Molecular formula of compound If both reactants react completely is
A) N20
B) NO2
C) N2O3
D) N2O5

Answer 1

The correct answer is option C – N2O3  
 
According to the given statement, the equation will be -

10 ml of NxOy + 30 ml of H2 gives 10 ml of N2 + H2O  
 
Assuming that 1 mol of the compound is used, the partially balanced equation will be   1NxOy + 3H2 gives 1N2 + H2O  
 
By balancing the N, H, and O atoms on both the sides, we get the equation as –   N2O3 + 3H2 ⟶ N2 + 3H2O  

Therefore, the formula of the compound is N2O3.

Answer 2

Answer:n203

Explanation:

At STP 1 mole of any gas occupies 22.4 L. Hence, the volume of the gases can be correlated to the number of moles of gases. 10 ml of compound reacts with 30 ml of hydrogen to produce water and 10 ml of nitrogen. Thus, for every one mole of the compound, 3 moles of hydrogen reacts to produce water and 1 mole of nitrogen.

X

+

3

H

2

→

H

2

O

+

N

2

This equation will be balanced when the formula of the compound is ,

N

2

O

3

,

N

2

O

3

+

3

H

2

→

3

H

2

O

+

N

2