10 ml of gaseous hydrocarbon on combustion gives 40 ml of co2 and 50 ml of h2o. the hydrocarbon is?
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Provided they are all gases then the formula is going to be
C4H10
they key here is that 1 mole of any ideal gass occupies the same volume as 1 mole of any other ideal gas under the same conditions of temperature and pressure. So, since the same volume of any ideal gas has the same number of moles then you can treat the ratio of volumes as the ratio of moles.
the ratio of volumes is
10 : 40 : 50
1 : 4 : 5
all the Carbon from the hydrocarbon is in the CO2
10 ml of hydrocarbon produces 40 ml CO2,
1 : 4 ratio
So 1 mole hydrocarbon has 4 moles Carbon
All the H ends up in the water
10 ml hydrocarbon produces 50 ml water,
1 : 5 ratio,
but also each water has 2 H atoms
So 1 mole hydrocarbon has 10 moles Hydrogen
which gives
C4H10
C4H10
they key here is that 1 mole of any ideal gass occupies the same volume as 1 mole of any other ideal gas under the same conditions of temperature and pressure. So, since the same volume of any ideal gas has the same number of moles then you can treat the ratio of volumes as the ratio of moles.
the ratio of volumes is
10 : 40 : 50
1 : 4 : 5
all the Carbon from the hydrocarbon is in the CO2
10 ml of hydrocarbon produces 40 ml CO2,
1 : 4 ratio
So 1 mole hydrocarbon has 4 moles Carbon
All the H ends up in the water
10 ml hydrocarbon produces 50 ml water,
1 : 5 ratio,
but also each water has 2 H atoms
So 1 mole hydrocarbon has 10 moles Hydrogen
which gives
C4H10
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