Question

10 ml of N/2 HCl ,30 ml of N/10 HNO3, 75 ml of N/5 H2SO4 are mixed together .the normality of resulting solution

Answer 1

Answer: The normality of the resulting solution is 0.2 N.

Explanation:

To calculate the normality of the solution after mixing 3 solutions, we use the equation:

$N=\frac{N_1V_1+N_2V_2+N_3V_3}{V_1+V_2+V_3}$

where,  

$N_1\text{ and }V_1$ are the normality and volume of the HCl  

$N_2\text{ and }V_2$ are the normality and volume of the $HNO_3$  

$N_3\text{ and }V_3$ are the normality and volume of the $H_2SO_4$  

We are given:  

$N_1=\frac{N}{2}=0.5N\\\\N_2=\frac{N}{10}=0.1N\\\\N_3=\frac{N}{5}=0.2N\\\\V_1=10mL\\V_2=30mL\\V_3=75mL$  

Putting all the values in above equation, we get:

$N=\frac{(0.5\times 10)+(0.1\times 30)+(0.2\times 75)}{10+30+75}\\\\N=0.2N$

Hence, the normality of the resulting solution is 0.2 N

Answer 2

Answer:

=0.2N

Explanation:

you try,and I hope this is the correct process.