Question

10 ml of sodium hydroxide solution is used to completely neutralize 8 ml of solution of HCL if you take 20 ml of the same solution what will be the amount of HCL required to neutralize it

Answer 1

mass is always conserved
let x be the amount of HCl
8/10=x/20
10x=160
    x=16 ml
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Answer 2

Answer:

16 ml of HCL requires to neutralize, 20 ml of NaOH

Explanation:

10 ml of NaOH requires to neutralize 8 ml of HCL

If, 20 ml of NaOH requires to neutralize = ? amount of HCL

10 ml of NaOH  = 8 ml oh HCL $\rightarrow$ equation 1

20 ml of NaOH = x $\rightarrow$ equation 2

Cross multiply equation (1) and (2)

10 $\times$ x  = 20 $\times$ 8

x = 160/10

x = 16 ml