Question

A stone is dropped from a cliff at 2:30:30 p.m. (hour: minute:second). Another stone is dropped from the same point at 2:30:31 p.m. Find the separation between the stones at (a) 2:30:31 p.m., (b) 2:30:35 p.m.

Answer 1

(a)At 2:30:31 p.mTime of travel of first stone=1 sDistance travelled by first stone:s1=ut+12gt2    =0+12×9.8×12    =4.9 mTime of travel of second stone=0Distance travelled by second stone:s2=ut+12gt2    =0+12×9.8×02    =0Distance of separation=s1−s2                                         =4.9−0                                          =4.9 m−−−−−−−−−−−−−−−−−−−−−−−−−−(b)At 2:30:35 p.mTime of travel of first stone=5 sDistance travelled by first stone:s1=ut+12gt2    =0+12×9.8×52    =122.5 mTime of travel of second stone=4 sDistance travelled by second stone:s2=ut+12gt2    =0+12×9.8×42    =78.4 mDistance of separation=s1−s2                                         =122.5−78.4                                          =44.1 m

Answer 2

Answer:

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