A ball is thrown upwards from the surface of the moon with a velocity of 19.6 m/s. (a) How much time will it take to attain the maximum height? (b) How high will it go?
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Answered by
142
v = 0, u = 19.6m/s, g = -9.8m/s²( as ball is thrown upwards)
v = u + at
0 = 19.6 + (-9.8)×t
-19.6 = - 9.8t
t = 20 sec
Therefore, the time taken to attain the maximum height is 20 sec.
2gh = v² - u²
2×-9.8×h = (0)² - (19.6)²
-19.6 = 0 - 19.6 × 19.6
-19.6h = -(19.6×19.6)
h = 19.6 * 19.6 / 19.6
h = 19.6 m
Therefore, the ball will go 19.6 metres high.
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v = u + at
0 = 19.6 + (-9.8)×t
-19.6 = - 9.8t
t = 20 sec
Therefore, the time taken to attain the maximum height is 20 sec.
2gh = v² - u²
2×-9.8×h = (0)² - (19.6)²
-19.6 = 0 - 19.6 × 19.6
-19.6h = -(19.6×19.6)
h = 19.6 * 19.6 / 19.6
h = 19.6 m
Therefore, the ball will go 19.6 metres high.
pls mark the brainliest
realsujaykumar:
Good explanation.....
Answered by
22
Explanation:
moon has value of g = 1.625 m/s^2
so calculate accordingly
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