If sin(A-B) =1/2, cos(A+B)=1/2, 0°<A+B_<90°,A>B,find A and B
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sin(A-B)=1/2
sin(A-B)=sin 30
A-B=30 equation no 1
cos (A+B)=1/2
cos(A+B)=cos 60
A+B=60 equation no 2
A-B=30
A+B=60
2A=90
A=45
substituting a in equation 1
B=15
sin(A-B)=sin 30
A-B=30 equation no 1
cos (A+B)=1/2
cos(A+B)=cos 60
A+B=60 equation no 2
A-B=30
A+B=60
2A=90
A=45
substituting a in equation 1
B=15
hannan31:
it's very helpful
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