Chemistry, asked by rsethu, 6 months ago

10 mol H2 react with 6 mol O2 and form water.identify the limiting reagent, calculate mass of water formed and mass of unreacted substance​

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Answered by nikunjc971
2

Explanation:

10 g of hydrogen and 64 g o...

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Asked on October 15, 2019 by

Allenraj Jeet

10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount to water produced in this reaction will be:

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ANSWER

2H

2

+O

2

→2H

2

O

10 g of hydrogen (molar mass 2 g/mol) =

2 g/mol

10 g

= 5 mol

64 of oxygen (molar mass 32 g/mol) =

32 g/mol

64 g

= 2 mol

As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.

2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.

Here, oxygen is the limiting reagent and hydrogen is the excess reagent

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