10 mol H2 react with 6 mol O2 and form water.identify the limiting reagent, calculate mass of water formed and mass of unreacted substance
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10 g of hydrogen and 64 g o...
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Asked on October 15, 2019 by
Allenraj Jeet
10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and exploded. Amount to water produced in this reaction will be:
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ANSWER
2H
2
+O
2
→2H
2
O
10 g of hydrogen (molar mass 2 g/mol) =
2 g/mol
10 g
= 5 mol
64 of oxygen (molar mass 32 g/mol) =
32 g/mol
64 g
= 2 mol
As per the balanced chemical equation, 1 mole of oxygen will react with 2 moles of hydrogen to form 2 moles of water.
2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water.
Here, oxygen is the limiting reagent and hydrogen is the excess reagent
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