10 mol of concentrated h2so4(18M) is diluted to on litre the approximate strength of the dilute acid is
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M1V1 = M2V2
18 x 10 = M2 x 1000
M2 = 18/100 = 0.18 molar
Now,
Normality = x x molarity
Where, x = mol.wt/equivalent wt.
= 98/49 = 2
Thus,
Normality = 2 x 0.18
= 0.36 N
Hence, the strength of dilute acid is 0.36 N
18 x 10 = M2 x 1000
M2 = 18/100 = 0.18 molar
Now,
Normality = x x molarity
Where, x = mol.wt/equivalent wt.
= 98/49 = 2
Thus,
Normality = 2 x 0.18
= 0.36 N
Hence, the strength of dilute acid is 0.36 N
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