Question

10.
Mr. Gupta divides 81,000 among his three children, Ashok, Mohit and Geeta, in such
a way that Ashok gets four times what Mohit gets and Mohit gets 2.5 times what Geeta
gets. Find the share of each of them.
105​

Answer 1

GIVEN :–

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• Mr. Gupta divides 81,000 among his three children, Ashok, Mohit and Geeta.

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• A way that Ashok gets four times what Mohit gets and Mohit gets 2.5 times what Geeta gets.

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TO FIND :–

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• Find the share of each of them = ?

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SOLUTION :–

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• Let the share of Geeta is 'x' .

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• Share of Mohit = (2.5) x

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• And the share of Ashok = (4)(2.5) x = 10 x

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▪︎ Total Amount = 81,000

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$\bf \implies Geeta's \: \: share + Mohit's \: \: share + Ashok's share = 81000$

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$\bf \implies x + 2.5x + 10x= 81000$

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$\bf \implies 3.5x + 10x= 81000$

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$\bf \implies 13.5x = 81000$

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$\bf \implies x = \dfrac{81000}{13.5}$

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$\implies \large{ \boxed{ \bf x = 6000}}$

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▪︎ Hence –

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• Geeta's share = 6,000

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• Mohit's share = 15,000

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• Ashok's share = 60,000

Answer 2

$\large{\red{\underline{\underline{\bold{Given:-}}}}}$

• Mr. Gupta divides Rs.81000 among his three children Ashok, Mohit and Geeta.

• Ashok gets four times of what Mohit gets.

• Mohit gets 2.5 times of what Geeta gets.

$\large{\blue{\underline{\underline{\bold{To\:Find:-}}}}}$

• The share of each of them

$\large{\green{\underline{\underline{\bold{Solution:-}}}}}$

According to the given question:-

Let the share of Geeta be x

The share of Mohit = 2.5x

Share of Ashok = 4(2.5x) = 10x

Total amount shared among the three = 81000

So:-

$\sf \implies x + 2.5x + 10x = 81000$

$\sf \implies 13.5x = 81000$

$\sf \implies x = \dfrac{81000}{13.5}$

$\sf \implies x = 6000$

Therefore:-

Share of Geeta = x = Rs. 6000

Share of Mohit = 2.5x = 2.5 × 6000 = Rs. 15000

Share of Ashok = 10x = 10× 6000 = 60000

Hence;

$\large \boxed{ \sf \rightarrow Share \: of \: Geeta = Rs.6000}$

$\large \boxed{ \sf \rightarrow Share \: of \: Mohit= Rs.15000}$

$\large \boxed{ \sf \rightarrow Share \: of \: Ashok = Rs.60000}$