10% of X + 20% of Y = 24 3x-y= 20
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Answered by
111
Hi ,
10% of x + 20% of y = 24
=> ( 10/100 )x + ( 20/100 ) y = 24
=> ( 10/100 ) [ x + 2y ] = 24
=> ( 1/10 ) ( x + 2y ) = 24
=> x + 2y = 240 -----( 1 )
3x - y = 20
=> y = 3x - 20 ---( 2 )
Substitute y = 3x - 20 in equation ( 1 )
x + 2( 3x - 20 ) = 240
=> x + 6x - 40 = 240
=> 7x = 240 + 40
=> 7x = 280
x = 280/7
x = 40
Substitute x = 40 in equation ( 2 ),
we get
y = 3 × 40 - 20
y = 120 - 20
y = 100
Therefore ,
x = 40 , y = 100
I hope this helps you.
: )
10% of x + 20% of y = 24
=> ( 10/100 )x + ( 20/100 ) y = 24
=> ( 10/100 ) [ x + 2y ] = 24
=> ( 1/10 ) ( x + 2y ) = 24
=> x + 2y = 240 -----( 1 )
3x - y = 20
=> y = 3x - 20 ---( 2 )
Substitute y = 3x - 20 in equation ( 1 )
x + 2( 3x - 20 ) = 240
=> x + 6x - 40 = 240
=> 7x = 240 + 40
=> 7x = 280
x = 280/7
x = 40
Substitute x = 40 in equation ( 2 ),
we get
y = 3 × 40 - 20
y = 120 - 20
y = 100
Therefore ,
x = 40 , y = 100
I hope this helps you.
: )
Answered by
39
(10/100)x+(20/100)y=24
(1/10)x+(1/5)y=24
(x/10)+(y/5)=24
2(x+3y/10)=24
x+6y/10=24
x+6y=24×10
x+6y=240
x=240÷6
x=40
It's substitute
3x-y=20
3×40-y=20
120-y=20
-y=20-120
y=100
(1/10)x+(1/5)y=24
(x/10)+(y/5)=24
2(x+3y/10)=24
x+6y/10=24
x+6y=24×10
x+6y=240
x=240÷6
x=40
It's substitute
3x-y=20
3×40-y=20
120-y=20
-y=20-120
y=100
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