Question

10 ओम प्रतिरोध तथा 10 हेनरी प्रेरकत्व की एक कुण्डली 50 वोल्ट की बैटरी से जोड़ी गई है। कुण्डली में संचित ऊर्जा
(a) 125 जूल
(b) 62.5 जूल
(C) 250 जूल
(d) 2500 जूल

Answer 1

Answer:

2500 joule ye hai shayed

Answer 2

The energy stored in the inductor is 125 Joules.

Explanation:

Given that,

Resistance of the coil, R = 10 ohms

Inductance of the inductor, L = 10 H

Voltage of the battery, V = 50 volt

According to Ohm's law :

$V=IR\\\\I=\dfrac{V}{R}\\\\I=\dfrac{50}{10}=5\ A$

The energy stored in the inductor is given by :

$E=\dfrac{1}{2}LI^2$

I is the current

$E=\dfrac{1}{2}\times 10\times (5)^2$

E = 125 Joules

So, the energy stored in the inductor is 125 Joules. So, the correct option is (A). Hence, this is the required solution.

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Energy stored in the inductor

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