10. One gram of the silver salt of an organic dibasic
acid yields, on strong heating, 0.5934 g of silver.
If the weight percentage of carbon in it 8 times
the weight percentage of hydrogen and half the
weight percentage of oxygen, determine the
molecular formula of the acid. (Atomic weight of
Ag - 108]
(A)C,H,O,
(8) C.H.O.
(C) C,H,O,
(0) C,H,O,
Answers
Answer:
sol
n
: 10 ml of compound C
n
H
2n+2
O
m
is mixed with 60 ml of O
2
C
n
H
2n+2
O
m
+(
4
7n
−
2
m
)O
2
→nCO
2
+(
2
2n+2
)H
2
O
After combination C
n
H
2n+2
O
m
is compound and total volume = 45 ml
Since CO
2
is acidic, KOH abroes CO
2
and volume
remaining = 15 ml =V
O
2
(excerr)
∴V
CO
2
=(45−15)ml=30ml
Then, after treating with KOH the volume of gas remaining is 15 ml.
∴(60−15)ml=45ml of O
2
has reacted
Acc. to Avogadro law,
ratio of moles = ratio of volume
∴
CO
2
O
2
=
n
2
zn
−
2
m
=
30
45
45n=30(
2
7n
−
2
m
)
∴n=
4
1
m=0.25m
C
0.25m
H
0.50m+2
O
m
≡C
n
H
2n+2
O
m
if m=1 then, formula is C
0.25
H
2.5
O
solution
Answer:
Explanation:
s weight of silver is given after heating is 0.6g so weight of acidic part is 0.4g by the given weight of Ag we can find moles of Ag by this we can find moles of compound.moles of compound = moles of Ag / 2 this 2 is due to dibasic