Computer Science, asked by snehapaherwar210, 1 year ago

10 parties want to exchange messages securely using some symmetric key encryption technique like AES. The number of distinct key values required will be

Answers

Answered by ksrksheeraja
10

Answer:

45

Explanation:

For symmetric keys or private key cryptographic techniques, the number of distinct key values can be calculated using the formula

(n(n-1)) /2  or nC2

where n -> no. of different parties involved

Therefore, for 10 parties it would be:

(10(10-1)) / 2 = (10*9)/2 = 90/2 = 45 (Ans)

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