Question

10 percent ofx+20percent of y=24 and 3x-y=20 solve by substituition method

Answer 1

Answer:

We obtained the value of x = 40 and y = 100 for the given equations using substitution method.

Step-by-step explanation:

Consider the given equations,

10 percent of x+20 percent of y=24  

We can write it in more simplified form as,

$\frac{10}{100}x+\frac{20}{100}y=24$

Solving further, we get

$x+2y=240$  ...............(1)

also given  $3x-y=20$ .............(2)

Since, we have to solve by substitution method,

From (1) , $x=240-2y$  ..........(3)

Put the above value of x in equation (2), We get

$\Rightarrow 3(240-2y)-y=20$

$\Rightarrow 720-6y-y=20$

$\Rightarrow -7y=20-720$

$\Rightarrow -7y=-700$

$\Rightarrow y=100$

We get y= 100 , put in (3) we get,

$x=240-2(100)$

$\Rightarrow x=240-200$

$\Rightarrow x=40$

Thus, We obtained the value of x = 40 and y = 100 for the given equations using substitution method.