Question

10. Rajon covers a certain distance between his home
and college by cycle. Having an average speed of
20 km/h, he is late by 20 min. However, with o
speed of 30 km/h, he reaches his college 10 min
earlier. Find the distance between his house and
college
​

Answer 1

Answer:

Okey

Lets start

If distance is constant

Speed = 1/ time

So, speed 1 : Speed 2 = time 2 : time 1

30 :40 = T2 : T1…………….Note( 1)

Let actual time = t

Ac. To question

Lately (t1) = t +20

Early (t2) =t -10

See note 1

30 /40 = T2 /T1

30 /40=t−10/t+20=t−10/t+20

3/4 ==t−10/t+20=t−10/t+20

3t +60 = 4t -40

T =100 min.

T = 1 hr 40 min.

Average speed = 30 km/hr

Distance =30×(1+40/60)30×(1+40/60)

=30× 5/3

=50 km

All the best

Cheers!

Just change the kilometers alone......

Hope it helps you.

Answer 2

1 st answer is correct....