Question

10) show that 3 - 5√7 is irrational​

Answer 1

Answer:

.................................

.........

Answer 2

irrational number......

Let us assume to the contrary that 3√5-7 is a rational no.

Such That ,

3√5-7=p/q {where, p and q are integers having no common factors}.

3√5=p/q+7

3√5=.p+7q/q

√5= p+7q/3q

where , √5 and p+7q/3q are rational numbers.

But this contradicts the fact that √5 is irrational.

Therefore,3√5-7 is an irrational no.

Let us assume to the contrary that 3√5-7 is a rational no. Such That , 3√5-7=p/q {where, p and q are integers having no common factors}. ... Therefore,3√5-7 is an irrational no.