10.Show with the help of chemical & word equation the chemical
reaction between
(a) Vinegar and baking soda.
(b) Carbon dioxide and lime water.
(c) Burning of magnesium ribbon.
(d) Magnesium oxide and water.
(e) Rusting of iron & Copper sulphate and iron.
Answers
(a) Vinegar and baking soda.
The overall chemical reaction between baking soda (sodium bicarbonate) and vinegar (weak acetic acid) is one mole of solid sodium bicarbonate reacts with one mole of liquid acetic acid to produce one mole each of carbon dioxide gas, liquid water, sodium ions, and acetate ions.
The reaction proceeds in two steps. The first reaction is a double displacement reaction, while the second reaction is a decomposition reaction.
The baking soda and vinegar reaction can be used to produce sodium acetate, by boiling off or evaporating all the liquid water.
(b) Carbon dioxide and lime water.
CaCO3 +H20This means that the carbon dioxide and limewater react to produce calcium carbonate and water. ... CO2(g) + Ca(OH)2(aq) -----> CaCO3(s) + H2O(l)The white milky suspension/precipitate is caused by the formation of calcium carbonate and explains the limewater test for carbon dioxide.
In its equation form that makes: CO2 + Ca (OH)2 -----> ? CO2 + Ca(OH)2 —-> CaCO3 + H2O
(c) Burning of magnesium ribbon.
The ribbon burns with a bright white light. Intense heat is also produced in this reaction. Here, when magnesium burns, it reacts with the oxygen found in air to form a powdery ash called magnesium oxide. Chemical equation: Magnesium plus Oxygen gives Magnesium oxide.
(d) Magnesium oxide and water.
Magnesium burns in steam to produce white magnesium oxide and hydrogen gas. Very clean magnesium ribbon has a very slight reaction with cold water. After several minutes, some bubbles of hydrogen form on its surface, and the coil of magnesium ribbon usually floats to the surface.
(e) Rusting of iron & Copper sulphate and iron.
Fe + CuSO₄ = FeSO₄ + Cu (iron displaces copper in the salt solution; the iron dissolves, turning into solution, and metallic copper of a reddish color is released).
Answer:
(a) NaHCo3 + CH3COOH= Co2 +H2O + Na+ CH3OO
(b) Ca(OH)2(aq) + CO2(g) → CaCO3(s) + H2O
(c) 2Mg + O2 = 2MgO
(d) MgO + H2O = Mg(OH)2
(e) Fe(s)+CuSO4(aq)⟶FeSO4(aq)+Cu(s)