10.
( sin A + cosec A ) 2 + ( cos A + sec A ) 2 = 7 + tan 2 A + cot 2 A
Answers
Answered by
0
Answer:
(sinA+cscA)
2
+(cosA+secA)
2
=sin
2
A+csc
2
A+2sinAcscA+cos
2
A+sec
2
A+2cosAsecA .......As[a²+b²+2ab=(a+b)²]
=sin
2
A+csc
2
A+2sinA×
sinA
1
+cos
2
A+sec
2
A+2cosA
cosA
1
.
........... since secA=
cosA
1
and cscA=
sinA
1
=sin
2
A+csc
2
A+2+cos
2
A+sec
2
A+2
=(sin
2
A+cos
2
A)+csc
2
A+sec
2
A+4
=1+1+cot
2
A+1+tan
2
A+4 ........... since csc
2
A=1+cot
2
A and sec
2
A=1+tan
2
A
=7+tan
2
A+cot
2
A
Hence proved.
Answered by
0
Answer:
(sin^2A + Cosec^2A + 2.SinA.CosecA) + (Cos^2A + Sec^2A + 2.CosA.SecA)
sin^2A + Cos^2A + Cosec^2A + 2SinA.1/sinA + Sec^2A + 2.CosA.1/CosA
1 + 2+ 2 + Cosec^2A + Sec^2A
5 + 1 + Cot^2A + 1 + Tan^2A
7 + Tan^2 + Cot^2A
Hope this helps you
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