Math, asked by dhirendramishr13, 3 months ago

10. Suppose the standard deviation of the series kį, kz, kz, .... k, is 5. What will be the standard
deviation of the following series ?
s = 5
(1) k, +2, k, + 2, kg + 2, ..., ky + 2
(ii) 3k,, 3k, 3k3 3k
(a) (i) 7 (ii) 3
(b) (i) 5 (ii) 3 (c) (i) 5 (ii) 15 (d) (i) 7 (ii) 15
then​

Answers

Answered by yadavsv09
4

Answer:

S.D=

n

∑(x−x)

2

x

ˉ

=

4

=

4

−1+0+1+k

=

4

k

Now

5

=

4

(−1−

4

k

)

2

+(0−

4

k

)

2

+(1+

4

k

)

2

+(k−

4

k

)

2

⇒5×4=2(1+

16

k

)

2

+

8

5k

2

⇒18=

4

3k

2

⇒k

2

=24

⇒k=2

6

.

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