10 th class maths mensuration see the picture and answer
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radius= 6m
height=8m
Volume= 1/3 * 22/7 * 6 * 6 * 8
therefore volume of rice heap= 301.59 m^3
Canvas cloth required = curved surface area= 22/7 * 6 * 10 [ l=10 by Pythagoras theorem]
therefore canvas cloth required =188m
height=8m
Volume= 1/3 * 22/7 * 6 * 6 * 8
therefore volume of rice heap= 301.59 m^3
Canvas cloth required = curved surface area= 22/7 * 6 * 10 [ l=10 by Pythagoras theorem]
therefore canvas cloth required =188m
adityavarman:
Answer for question 9: l=37
188m^(area of cloth,sry)
188m^2
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1
1) height of cone is 8m
diameter = 12m
therefore, radius =d÷2=6m
volume of heap of rice = 1/3 π r2 h (here 2 is square)
.............................=1/3 * 3.14 * (6)2 *8 (here 2 is square of 6 )
=314.96 cm3
2) Curved / Lateral surface area of cone = 4070 cm sq
diameter of cone = 70 cm sq => radius = 35 cm
=> πrl =4070
=> 22/7*35*l =4070
=> l = 4070÷110
Therefore, l= 37 cm
slant height of cone = 37 cm
diameter = 12m
therefore, radius =d÷2=6m
volume of heap of rice = 1/3 π r2 h (here 2 is square)
.............................=1/3 * 3.14 * (6)2 *8 (here 2 is square of 6 )
=314.96 cm3
2) Curved / Lateral surface area of cone = 4070 cm sq
diameter of cone = 70 cm sq => radius = 35 cm
=> πrl =4070
=> 22/7*35*l =4070
=> l = 4070÷110
Therefore, l= 37 cm
slant height of cone = 37 cm
sorry 1 st answer is wrong follow other answer . second answer is correct
real so sorry
I have mistaken
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