Math, asked by mukeshmeena23274, 1 month ago

10. The area of a rhombus whose diagonals are of lengths 10 cm and 8.2 cm is: *​

Answers

Answered by MATHISWORLD
0

Answer:

41

Step-by-step explanation:

ans : 0.5 x 10 x 8.2= 41 cm square

mark me the brainiest

Answered by AestheticSoul
4

Given

  • Length of the first diagonal = 10 cm
  • Length of the second diagonal = 8.2 cm

To find

  • Area of rhombus

Solution

Formula to be used :-

Area of rhombus = ½ × d× d

where,

  • D₁ = First Diagonal
  • D₂ = Second diagonal

Substituting the values,

⟶ ½ × 10 × 8.4

⟶ 5 × 8.4

42 cm²

Therefore, area of rhombus = 42 cm²

______________________________

Some formulae :-

  • Area of square = side × side
  • Perimeter of square = 4 × side
  • Area of rectangle = l × b
  • Perimeter of reactangle = 2(l + b)
  • Total surface area of cube = 6 × side²
  • Total surface Area of cuboid = 2(lb + bh + hl)
Similar questions