Question

10. The force between two parallel wire 2 x 10-7 Nm-1, placed 1 m apart to each other in vacuum. The electric current flowing through * the wires is: O 12 O zero O 5 5 x 106 A O 2 x 10-7 A mcq​

Answer 1

Answer:

Given: I

1

=I

2

=1 A

Distance between the wires, d=1 m

Force of attraction per unit length, f=

2πd

μ

0

I

1

I

2

N/m

∴ f=

2π×1

4π×10

−7

×(1)(1)

=2×10

−7

Answer 2

Given: The force between two parallel wire 2 x 10-7 Nm-1, placed 1 m apart to each other in vacuum.

To find: The electric current flowing through the wires

Explanation: Let current flowing through the wires be i, force be f, u be the permeability in vacuum and r the distance between them.

The force per unit length on a wire is given by the formula when current is equal in both wires:

$f = \frac{u \times 2 {i}^{2} }{4\pi \times r}$

u/4π is a constant whose value is = 10^-7

Using this:

=>$2 \times {10}^{ - 7} = \frac{ {10}^{ - 7 } \times 2 \times {i}^{2} }{1}$

=>${i}^{2} = 1$

=> i = 1 A

Therefore, the electric current flowing through the wires is 1 A.