10. The length of a rectangle is twice its breadth. If the length of the rectangle is increased by 10%
while its breadth is decreased by 10%, determine the percentage change (if any) in its perimeter.
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Answer:
Increase by10/3%
Step-by-step explanation:
Let length and breadth be x and y respectively
P=2(l+b)
=2(x+y)
=2(2y+y) ....(x=2y)
=6y
New l=x+x/10=11x/10=22y/10
New b=y-y/10=9y/10
New P=2((22+9)y/10
=31y/5
Increase=(31y/5)-6y=(31y-30y)/5=y/5
Increase%=(y/5)÷6y×100%=100y/30y=10/3%
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