Question

10. The length of a rectangle is twice its breadth. If the length of the rectangle is increased by 10%
while its breadth is decreased by 10%, determine the percentage change (if any) in its perimeter.​

Answer 1

Answer:

Increase by10/3%

Step-by-step explanation:

Let length and breadth be x and y respectively

P=2(l+b)

=2(x+y)

=2(2y+y) ....(x=2y)

=6y

New l=x+x/10=11x/10=22y/10

New b=y-y/10=9y/10

New P=2((22+9)y/10

=31y/5

Increase=(31y/5)-6y=(31y-30y)/5=y/5

Increase%=(y/5)÷6y×100%=100y/30y=10/3%