10. The perimeter of a rhombus is 100 cm and one of its diagonals is 48 cm. Find the length of the other
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2
Answer:
Perimeter of rhombus of side a=4a
⇒4a=100
⇒a=25cm.
Let AC=48cm
As diagonals bisect each other in rhombus
⇒AO=24cm
By Pythagoras theorem in ΔAOD, AD
2
=AO
2
+OD
2
⇒OD
2
=
625−576
=
49
=7cm
⇒BD=14cm
Area =
2
1
d
1
d
2
=
2
1
(14)(48)=7×48=336cm
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0
Answer:
perimeter=100
4a=100
a=100/4
a=25 this is your right answer
Step-by-step explanation:
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