Question

10. The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction 2A + 4B 3C + 4D, when 5 moles of A react with 6 moles of B. Then i. Which is the limiting reagent ? ii. Calculate the amount of C formed ?

Answer 1

Answer:

i) B is limiting reagent.

ii) 2 moles of C

Explanation:

Reaction is 2A + 4B ---> 3C + 4D

i) moles of A reacted = 5 mol

=> mol to stoichiometric coefficient ratio = 5 mol / 2 = 2.5 mol

for B,  mol to stoichiometric coefficient ratio = 6 mol / 4 = 1.5 mol

Since mol to stoichiometric coefficient ratio is least for B So limiting reagent is B, and it will decide the yield of product.

ii) Since B will decide the yield of product.

4 mol of B gives = 3 mol of C

=> 6 mol of B will give = (3 mol / 4 mol) * 6 mol = 2 mol of C

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