Question

10. The sides of a rectangle are in the ratio 3 : 2. If its
perimeter is 50 cm, find its sides.​

Answer 1

Answer:

Length of the rectangle is 15 cm and breadth of the rectangle is 10 cm.

Step-by-step explanation:

Given :-

• The sides of a rectangle are in the ratio 3:2.
• Perimeter of the rectangle is 50 cm.

To find :-

• Its sides.

Solution :-

★ The sides of the rectangle are in the ratio 3:2.

Consider,

• Length of the rectangle = 3x cm
• Breadth of the rectangle = 2x cm.

Formula used :

${\boxed{\sf{Perimeter\:of\: rectangle=2(length+breadth)}}}$

★ Perimeter of the rectangle is 50 cm.

According to the question ,

2(3x+2x)=50

→ 3x+2x = 50/2

→ 5x = 25

→ x = 25/5

→ x = 5

★ Length of the rectangle = 3×5 = 15 cm

★ Breadth of the rectangle = 2×5 = 10 cm

___________________

Additional information :-

★ Area of rectangle = length× breadth

★ Diagonal of rectangle = √(length²+ breadth²)

★ Perimeter of square = 4 × side

★ Area of square = side²

Answer 2

Step-by-step explanation:

Let length of the rectangle be 3x and breadth be 2x.

Perimeter of rectangle = 2(l+b)

50 = 2(3x+2x)

50 = 2× 5x

5x = 50÷2

x = 25÷5

x = 5

Therefore, length of the rectangle = 3x = 3×5= 15cm

and, breadth of the rectangle = 2x= 2×5= 10cm