Question

10. The sides of rectangle are 3a2 + 2b and 5a2 – 4b. Find its perimeter.

Answer 1

Answer:

3a²+2b and 5a²- 4b

2(a+b)

2(3a²+2b+5a²-4b)

2(8a²-2b)

2×2(4a²-b)

16a²-4b

......

Answer 2

Answer:

Hey friend,

Here is the answer you are searching for,

Given,

Length = 5a²+4b

Breadth = 3a²+2b

Perimeter = 2( Length + Breadth)

= 2(5a²-4b + 3a²+2b)

= 2(8a²-2b)

= 16a²-4b

Therefore,

Perimeter = 16a²-4b

HOPE IT HELPS YOU.

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