10. The sides of rectangle are 3a2 + 2b and 5a2 – 4b. Find its perimeter.
Answers
Answered by
8
Answer:
3a²+2b and 5a²- 4b
2(a+b)
2(3a²+2b+5a²-4b)
2(8a²-2b)
2×2(4a²-b)
16a²-4b
......
Answered by
6
Answer:
Hey friend,
Here is the answer you are searching for,
Given,
Length = 5a²+4b
Breadth = 3a²+2b
Perimeter = 2( Length + Breadth)
= 2(5a²-4b + 3a²+2b)
= 2(8a²-2b)
= 16a²-4b
Therefore,
Perimeter = 16a²-4b
HOPE IT HELPS YOU.
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