Question

10. There are 156, 208 and 260 students in groups A, B and C, respectively. Buses are to be hired to take them for a field trip. Find the minimum number of buses to be hired, if the same number of students should be accommodated in each bus.

Standard:- 10

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Answer 1

HELLO !!....


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You should take H.C.F. of 156, 208 and 260.


=> HCF of 156 and 208

P.F. of 156 = 2×2×3×13
P.F. of 208 = 2×2×2×2×13
Therefore, H.C.F. of 156 and 208 = 2×2×13 = 52


=> Now , H.C.F. of 52 and 260

P.F. of 52 = 2×2×13
P.F. of 260 = 2×2×5×13
H.C.F. = 2×2×13 = 52

●Max. number of students per bus = 52

●Total number of students = 156+208+260 = 624 students.

●No. of buses = 624/52 = 12 buses.


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Hope it helps u !!!

good night :))

# Nikky

Answer 2

HOPE IT HELPS YOU ✌✌✌✌...