10. Three fair coins are tossed. If both heads
and tails appears, then the probability that exactly one head appears is
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Step-by-step explanation:
Three coins are tossed and hence the size of universal set is 23=8. The number of outcomes where both heads and tails occur are 6 (event a) i.e [HHT],HTH,[THH],[TTH],[THT],[HTT].
The number of outcomes where exactly one head appears is (event b) [TTH],[THT],[HTT]. If both heads and tails appear, probability that one head appears is
P(ab)=P(a)P(b∩a)=8683=21
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