10 turns of a wire are helically wrapped around a cylindrical tube with outside circumference 4 inches and length 9 inches. The ends of the wire coincide with the end of the same cylindrical element. Find the length of the wire.
Answers
Answer:
40 Inches
Step-by-step explanation:
There is not much information needed to solve this question. Since the no. of turns of wire are given along with the outer circumference, we can simply calculate the length of wire by multiplying circumference into total turns. Length of the tube is unnecessary here, There was not any need to put this.
So, total length = 4 * 10 = 40 Inches
Answer:
41 inches.
Step-by-step explanation:
A cylinder is just a curved rectangle. So the wire wrapped around it can be imagined as the rectangle's diagonal. So by applying Pythagoras theorem-
Length of wire will be 40 inches (as the circumference is 4 inches and it has been rolled ten times (ten turns)) and the breadth will be 9 inches i.e. the length of the cylinder.
[tex]a^2+b^2=c^2
L^2 = 40^2 + 92^2
L^2 = 1600 + 81
L^2 = 1681
L = 41
∴L = 41 [/tex]
So,
Length of wire = 41 inch
Hope it helps