Question

10. Two parallel sides of a trapezium are 58 cm and 42 cm. The other two sides are of

equal length which is 17 cm. Find the area of trapezium.
anyone help me out with this question
give me a detailed answer❣️​

Answer 1

SOLUTION:-

Answer

• Area of trapezium is 750cm²

Given

• Parallel sides are 58cm and 42cm

• Other two sides are 17 cm

To find

• Area of trapezium

Explanation

We know that,

Area of trapezium = 1/2×(Sum of parallel sides)× height

Let us Draw a perpendicular AE and BF from the vertex A and B onto the opposite side CD

( Shown in figure)

Since,

ACE is a right angled triangle

As AB and CD are parallel , when perpendicular are drawn ,

AB = EF = 42

Then

The remaining CE and FD will be

➡️ 58-42 / 2

➡️ 16/2

➡️ 8 cm

Now,

By pythagoras Theorem

For Triangle ACE

AC²= AE² + CE²

➡️ 17² = AE² + 8²

➡️ 289 = AE² + 64

➡️ 289-64 = AE²

➡️ 225 = AE²

➡️ AE = √225

➡️ AE = 15cm

Similarly

By pythagoras theorem

For Triangle BDF

DB² = BF²+ DF²

➡️ 17²= BF²+8²

➡️ 289 = BF²+64

➡️ 289-64=BF²

➡️ BF²= 225

➡️ BF= √225

➡️ BF = 15cm

Height = 15cm

Area of trapezium = 1/2(a+b)×h

➡️ 1/2×(58+42)×15

➡️ 1/2×100×15

Area = 750cm²

_______________________________

Answer 2

Answer:

hope this will help u ❤️